Python 'if' condition doesn't work with shorthand 'or' [duplicate]

This question already has an answer here:

What is wrong here on the method a|b==0 vs a==0 or b==0 ?

def validate(a,b,c):
print(a,b,c)
if (a|b == 0) or c == 0:
return "Invalid"
else:
return "Valid"
print("Test 1: ", validate(0,1,2))
print("Test 2: ", validate(0,1,0))


>0 1 2
Test 1: Valid


>0 1 0
Test 2: Invalid


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|

|

or

1 Answer
1

You seem to have confused python's or and |.

or

|

Understandable, given that the or operator in many langages is | (or more commonly ||).

|

||

This page lists python's operators

Try your example again, but using or instead of |

or

|

if (a or b == 0) or c == 0:


If I'm reading your question correctly however, I think you're trying to do this;

if (a == b == 0) or c == 0:


This is the shortcut-syntax in python for checking if both a and b is equal to 0.

a

b

EDIT: As per clarification;

Requirement is to confirm 0 is not passed as an argument to the function

If you can safely assume that your arguments are going to be ints, then I would take the following approach:

if a and b and c:
pass # valid
else:
pass # invalid


0 is falsey - so lets use the fact. Otherwise, there isn't really a 'shortcut' way to do what you're doing.

0

def validate(a,b,c): print(a,b,c) if (a or b == 0) or c == 0: return "Invalid" else: return "Valid" print("Test 1: ", validate(0,1,2)) print("Test 2: ", validate(0,1,0))

or

|

or

and

if a ==0 or b == 0 or c == 0

if 0 in (a,b,c)