TypeError error while using isin function to filter rows in Pandas

I met a TypeError error while using isin function to filter rows of my dataset in Pandas

df[~df['id'].isin('134399', '187013')]


The results:

df[~df['id'].isin('134399', '187013')]
Traceback (most recent call last):

File "<ipython-input-91-ba70cce02a1c>", line 1, in <module>
df[~df['id'].isin('134399', '187013')]

TypeError: isin() takes 2 positional arguments but 3 were given


Does someone know how to deal with this issue and can help me? Thanks.

1 Answer
1

You need to pass a single argument to isin (the extra one that's being counted in the 2 or 3 is self). You're passing two. That is, your argument should be a list containing the values you want to test against.

isin

self

df[~df['id'].isin(['134399', '187013'])]


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