How to create a variable that is char * so it can be passed to a function

I'm trying to pass an argument to a function that takes a char * as input:

char *

int nArgs = 0;
CommandLineToArgvW(GetCommandLineW(), &nArgs);
const int commandLineArgsBufferSize = 500;
char commandLineArgs[commandLineArgsBufferSize];
wcstombs(commandLineArgs, GetCommandLineW(), commandLineArgsBufferSize);
int result = Catch::Session().run(nArgs, &commandLineArgs);


Here is the function prototype.

int Session::run( int argc, char* argv );


I am getting a compiler error:

C2664 'int Catch::Session::run(void)': cannot convert argument 2 from 'char (*)[500]' to 'char *'

char*

char

1 Answer
1

The function is presumably intended to take the parameters of main() as arguments. So you want something like:

int main( int argc, char * argv ) {
int rv = Session::run( argc, argv );
}


If you wanted to construct the arguments yourself, something like:

void f() {
char * argv = {"foo", "bar" };
int rv = Session::run( 2, argv );
}


^

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.