Multi tool use

Python Find & Count Certain Word within (Strings) List Items

Hello dear Programmers,

I want to find certain words within List Items. My Input looks like this:

myInputList = ['HausestNNtHaus', 'gutentADJtgut', 'gehttVFINtgehen'...]


I want to find and count tNNt or tADJt or tVFINt.
The position of the words that I want to count is always the same, like you can see in the example.

I tried the following code, but I get the following error: ValueError too many values to unpack (expected 3)

from collections import Counter

myInputList = Counter([b for a,b,c in myInputList])
print(myInputList)


Actually, I can see why this code is not working. But I don't have another approach.

So my goal is to count the Part of Speach tags that are between the t.
So at the end I want to say: There are 5 NN, 4 ADJA...

split

t

Counter(s.split('t')[1] for s in myInputList)

4 Answers
4

Including the case when 't' not present

from collections import Counter
myInputList = ['HausestNNtHaus', 'gutentADJtgut', 'gehttVFINtgehen','xyz']
Counter([x.split('t')[1] for x in myInputList if 't' in x])


Convert into Dictionary

from collections import Counter
myInputList = ['HausestNNtHaus', 'gutentADJtgut', 'gehttVFINtgehen','xyz']
d=dict(Counter([x.split('t')[1] for x in myInputList if 't' in x]))
print(d['NN'])


Output:1

myInputList = ['HausestNNtHaus', 'gutentADJtgut', 'gehttVFINtgehen']

newList =
for i in myInputList:

newList.extend(i.split("t"))

from collections import Counter
Counter(newList)


gives

{'ADJ': 1,
'Haus': 1,
'Hauses': 1,
'NN': 1,
'VFIN': 1,
'gehen': 1,
'geht': 1,
'gut': 1,
'guten': 1}


If you want and you're sure that you want only the elements in the 2ND index, then you can simply do

myInputList = ['HausestNNtHaus', 'gutentADJtgut', 'gehttVFINtgehen']

newList =
for i in myInputList:

newList.append(i.split("t"))

from collections import Counter



onlySecond = [i[1] for i in newList]
dict(Counter(onlySecond))


will give you

{'ADJ': 1, 'NN': 1, 'VFIN': 1}


You can use collections.defaultdict. If there is a possibility of more than one value occurring in a list item, then you can remove break, which otherwise stops at the first match for a particular string.

collections.defaultdict

break

myInputList = ['HausestNNtHaus', 'gutentADJtgut', 'gehttVFINtgehen']
values = ['tNNt', 'tADJt', 'tVFINt']

from collections import defaultdict

d = defaultdict(int)

for item in myInputList:
for v in values:
if v in item:
d[v] += 1
break

print(d)

defaultdict(int, {'tADJt': 1, 'tNNt': 1, 'tVFINt': 1})


This should do it:

a, b, c = ('tNNt', 'tADJt', 'tVFINt')

myInputList = ['HausestNNtHaus', 'gutentADJtgut', 'gehttVFINtgehen']

print(len([i for i in myInputList if any(j in i for j in [a, b, c])]))
#3


print(len([i for i in myInputList if any(j in i for j in [a])]))

... for j in a

['t', 'N', 'N', 't']

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