C Programming -Linked List Implementation with characters

MY CODE:

#include<stdio.h>
#include<stdlib.h>

struct node{
char data;
struct node *next;
};

void main()
{ char A;
struct node *head,*ptr;
ptr=(struct node *)malloc(sizeof(struct node));
printf("Enter data for node 1 n");
scanf("%c",&ptr->data);
head=ptr;
int i=2;
while(1)
{
ptr->next=(struct node*)malloc(sizeof(struct node));
ptr=ptr->next;
printf("nEnter data for node %d:::n",i);
scanf("%c",&ptr->data);
ptr->next=NULL;
i=i+1;
printf("Do you want to continue Y OR N");
scanf("%c",&A);
if(A=='Y')
continue;
else
break;

}

struct node *temp;

temp=head;
while(temp!=NULL)
{
printf("%c=>",temp->data);
temp=temp->next;
}
printf("NULL");





}


For this code I can only enter the first character data after that it is skipping the scanf portion within the while loop.
But when I am doing the same code with integer it is giving me the right output.
Here if I replace the same code instead of having characters I replace it by integers it works fine.
I couldnt find a way to fix it.
Plz help.

scanf()

%c

%d

scanf()

Enter

'n'

1 Answer
1

As stated in the comments your problem lies not in the linked list implementation, but in the code lines here.

scanf("%c",&ptr->data); //line number 14

scanf("%c",&ptr->data); //line number 22

scanf("%c",&A); //line number 26


in all these lines %c consumes the new line character(n) instead of the users input.

To correct the issue, you can place a whitespace in front of the %c like this,

scanf(" %c",&ptr->data); //line number 14

scanf(" %c",&ptr->data); //line number 22

scanf(" %c",&A); //line number 26


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