How to Parse Date in java [duplicate]


How to Parse Date in java [duplicate]



This question already has an answer here:


Unparseable date: "Tue Jul 03 16:59:51 IST 2018" Exception

String date="Tue Jul 03 16:59:51 IST 2018";



i want to parse it.
My code is


SimpleDateFormat newformat=SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ssZ")
Date d=newformat.parse(date);



This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.





hum, you do you expect your pattern to parse your string ? it's just impossible, string is Day Month year, and pattern is year-month-day, you should learn to build pattern
– azro
Jul 3 at 9:35






Your pattern has to match the string you provide
– XtremeBaumer
Jul 3 at 9:36





SimpleDateFormat looks at the first element of the format pattern string, yyyy, this means 4-digit year. Then it looks at the first element of your date string, Tue. Tue cannot be a four digit year. Therefore it throws the exception (it probably only needs to look at the T to decide).
– Ole V.V.
Jul 3 at 13:51



SimpleDateFormat


yyyy


Tue


Tue


T





I recommend you avoid the SimpleDateFormat class. It is not only long outdated, it is also notoriously troublesome. Today we have so much better in java.time, the modern Java date and time API and its DateTimeFormatter.
– Ole V.V.
Jul 4 at 8:33


SimpleDateFormat


java.time


DateTimeFormatter




2 Answers
2



You are using old and quite problematic classes, especially Date.



For your example, perhaps consider using LocalDateTime


String date = "Tue Jul 03 16:59:51 IST 2018";
DateTimeFormatter format = DateTimeFormatter
.ofPattern("EEE MMM dd HH:mm:ss z yyyy");
LocalDateTime dateTime = LocalDateTime.parse(date, format);





I can’t decide whether I want to recommend ZonedDateTime over LocalDateTime here. The string includes a time zone abbreviation, so it could be considered a shame to throw it away from the outset. On the other hand, three and four letter time zone abbreviations are generally ambiguous, so if trying to parse it, we risk a result that conflicts with what was intended. LocalDateTime evades that problem.
– Ole V.V.
Jul 4 at 10:47


ZonedDateTime


LocalDateTime


LocalDateTime





@OleV.V. Funnily enough I wrote the answer initially with ZonedDateTime but edited it to LocalDateTime.
– notyou
Jul 4 at 10:55


ZonedDateTime


LocalDateTime



Since your pattern has to match the string you want to parse you need to adjust the pattern as following:


EEE MMM dd HH:mm:ss z yyyy



Infos gathered from the docs.



You should also use the new java.time API introduced with Java 8.


java.time


String s = "Tue Jul 03 16:59:51 IST 2018";
//Java 7 way
SimpleDateFormat newformat = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy");
Date d = newformat.parse(s);
//Java 8 way
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("EEE MMM dd HH:mm:ss z yyyy");
LocalDateTime dateTime = LocalDateTime.parse(s, formatter);

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