Multi tool use

How can I remove the fragment identifier from a URL?

I have a string containing a link. The link often has the form:

Is there a function in python that can remove "#something" from a link?

5 Answers
5

Just use split()

split()

>>> foo = "http://www.address.com/something#something"
>>> foo = foo.split('#')[0]
>>> foo
'http://www.address.com/something'
>>>


For Python 2 use urlparse.urldefrag:

>>> urlparse.urldefrag("http://www.address.com/something#something")
('http://www.address.com/something', 'something')


In python 3, the urldefrag function is now part of urllib.parse:

urldefrag

urllib.parse

from urllib.parse import urldefrag
unfragmented = urldefrag("http://www.address.com/something#something")

('http://www.address.com/something', 'something')


Try this:

>>> s="http://www.address.com/something#something"
>>> s1=s.split("#")[0]
>>> s1
'http://www.address.com/something'


You can assign away the unwanted part like so

fixed, throwaway = urldefrag(url)


where url is the fragmented address. This is a bit nicer than a split. I have not checked if it is faster or more efficient though.

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