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Regex for latitude with required 6 decimal places

I need a regex in Java that will check if a String representation of a double has required 6 decimal places. Before the decimal point, value can be positive or negative.

1.123456 - correct
-123123123.123456 - correct
123123123.123456 - correct
-123123123.123456 - correct

1.12345 - wrong
-.123456 - wrong
.123456 - wrong
.12345 - wrong
123456 - wrong


I tried:

^s*(?=.*[1-9])d*(.d{6})?s*$


but it doesn't cover all edges.

3 Answers
3

Try this:

^s*(-|+)?(0|[1-9]d*).d{6}s*$


See live demo.

This allows the first digits to be zero only if it's the only digit before the dot, eg 0.123456 is OK, but not 01.123456. .d{6} requires exactly 6 decimal places.

0.123456

01.123456

.d{6}

The valid input should

^s*

-

+

(-|+)?

d+

.

(d{6})

^s*

Try this:

^s*(-|+)?d+.(d{6})s*$


In your regex the positive lookahead (?=.*[1-9]) asserts that what is on the right side should contain a digit which will succeed for all examples. After that assertion you match zero or more digits d* followed by a part that optionally matches a dot and 6 digits (.d{6})? so this will match .588888 or also 1.

(?=.*[1-9])

d*

(.d{6})?

.588888

1

If you want to match an optional minus sign you could use -?

-?

For your example data you might use:

^-?d+.d{6}$

^-?d+.d{6}$

In Java:

String regex = "^-?d+.d{6}$";


Explanation

^

-?

d+.d{6}

$

Demo

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