SQL order groups in table without GROUP BY

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SQL order groups in table without GROUP BY



I have a quote_logs table where there are groups of logs(about 8 logs in each group). Every group has quote_log_group field which has the same value for the group(for example 1530599717507).



I need SQL statement to get all quote logs, sorted by the net_charge field in each group.
Rows in the table look like this:



enter image description here



Expected sample output:


*id* *net_charge* *quote_log_group*
5 - 110 - group1
7 - 120 - group1
2 - 130 - group1
4 - 140 - group1
3 - 150 - group1

11 - 110 - group2
15 - 120 - group2
12 - 130 - group2
13 - 140 - group2
14 - 150 - group2





Can you post the expected output? also, post what you have tried.
– Jignesh Patel
Jul 3 at 7:26





Most people here want formatted text, not images.
– jarlh
Jul 3 at 7:26





You can ORDER BY multiple columns. For instance first on quote_log_group followed by net_charge : ORDER BY quote_log_group, net_charge See: dev.mysql.com/doc/refman/8.0/en/sorting-rows.html
– KIKO Software
Jul 3 at 7:28





1 Answer
1



You can order the query by quote_log_group to get all the rows in the same group one of the other and then by net_charge:


quote_log_group


net_charge


SELECT *
FROM quote_logs
ORDER BY quote_log_group, net_charge






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